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Problem Solving (PS) | Ten years ago, the average age of a couple was 27 years old. Today

January 7, 2019, 12:00 am
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cfc198 wrote:

Ten years ago, the average age of a couple was 27 years old. Today also the average age of the couple and their baby is 27 years old. Find the present age of the baby.

A 4
B 3
C 2
D 5
E 7


Couple's age = x+y, Baby's age = z

Ten yearsAgo,
\(\frac{x+y}{2}\) - 10 =27
x+y-20 = 54
x+y=74

\(\frac{x+y+z}{3}\) =27
x+y+z = 81
z = 7

Correct Answer E
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Problem Solving (PS) | Re: When a subscription to a new magazine was purchased for m months, the

January 7, 2019, 12:00 am
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Problem Solving (PS) | Re: How many 7-digit even numbers less than 3,000,000 can be formed using

January 7, 2019, 12:00 am
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Data Sufficiency (DS) | Re: Is x a positive integer? (1) x > 0 (2) x^2 + 16 = 25

January 7, 2019, 12:00 am
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St. 1 - X>0 is insufficient as X can be a decimal no.
St. 2 - x^2+16=25 is insufficient as X can be either +3 or -3

Combining st. 1 and st.2 renders only one possible value of X, which is +3 and hence this combination is sufficient. Answer C
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Problem Solving (PS) | Re: If y is not equal to 4, x is not equal to 0, and (y^2 – 16)/(3x) = (y

January 7, 2019, 12:00 am
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Problem Solving (PS) | Re: A will was written such that an estate would be divided among five ben

January 7, 2019, 12:00 am
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Problem Solving (PS) | Re: Find the number of zeroes in 1142! × 348! × 17!

January 7, 2019, 12:00 am
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Hello from the GMAT Club BumpBot!

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Problem Solving (PS) | Re: What is the smallest possible distance between the point (0, 5) and an

January 7, 2019, 12:00 am
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Please the graph doesn’t make any sense.

When I graph I see 2 points between (0,5) and (0,3) and the perpendicular from (0,5) hits the line at x=-2, giving a 2,2,2root2 90degree triangle between 0,5 and 0,3(on the line).

Where am I wrong?

Or should I just memorize the formula and move on


u1983 wrote:

SajjadAhmad wrote:
What is the smallest possible distance between the point (0, 5) and any point on the line y = -x + 3?

A. 0
B. \(\frac{1}{\sqrt{2}}\)
C. 1
D.\(\sqrt{2}\)
E. 2

EG

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Problem Solving (PS) | Re: What is the range of the prime factors of m, if m = 2^5*3^11 - 9^6 -

January 7, 2019, 12:00 am
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lclarios91 wrote:

Archit3110 wrote:
Bunuel wrote:
What is the range of the prime factors of m, if \(m = 2^5*3^{11} - 9^{6} - 3^{11}\) ?

A. 0
B. 1
C. 2
D. 4
E. 5



\(m = 2^5*3^{11} - 9^{6} - 3^{11}\)

3^11(2^5-3-1)
3^11(28)
3^11(2^2*7)

range would be 7-2 = 5 IMOE



Where does the 3-1 comefrom?


Archit,

We can factor out 3^11 from 2^5*3^11 -(3^2)^6-3^11 ----> 2^5*3^11-3^12-3^11-----> 3^11(2^5-3-1)---->3^11(32-4)--->3^11(28) ---->3^11(2^2*7).
So the range will be 7 - 2 = 5
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Problem Solving (PS) | Re: Minimum of how many people are needed to have the probability of more

January 7, 2019, 12:00 am
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AnkitOrYadav wrote:

chetan2u wrote:
Bunuel wrote:

GMAT CLUB TESTS' FRESH QUESTION:



Minimum of how many people are needed to have the probability of more than 1/2 that at lease one of them was born on either on Monday or on Tuesday?

A. 2
B. 3
C. 4
D. 5
E. 6



Say there are only 2 person..
Prob = 2/7+2/7-2/7*2/7=4/7-4/49=24/49<1/2
Ans will be 3 because with 2, we had answer almost close to 1/2
No calculations requiredtherefore
B[/quote

Hi Experts,can you please explain Prob = 2/7+2/7-2/7*2/7 .
I am not able to understand this.


not so sure....but I think we are using the probability OR rule:

prob(A or B) = P(A) + P(B) - P(A and B)
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Problem Solving (PS) | If a sequence of consecutive integers of increasing value has a sum of

January 7, 2019, 12:00 am
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Bunuel wrote:

If a sequence of consecutive integers of increasing value has a sum of 63 and a first term of 6, how many integers are in the sequence?

(A) 11
(B) 10
(C) 9
(D) 8
(E) 7


because 63 sum=number of terms*mean,
try choices 9 and 7 as factors of 63
7 terms with mean of 9 works
E
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Problem Solving (PS) | Re: John buys R pounds of cheese to feed N people at a party. If N + P peo

January 7, 2019, 12:00 am
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R pound of Cheese for N people.
This means R/N pounds of cheese for 1 person.

Now, additional people= N+P-N=P
So, additional cheese required = P*R/N

Hence,E
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Problem Solving (PS) | Re: If x∇y=3x^2·y for all x and y, then 1∇(1∇1)=

January 7, 2019, 12:00 am
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I haven't understood the question stem itself, can someone explain theoretically what does the question actually imply? Image
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Problem Solving (PS) | Re: If (20!*20!)/20^n is an integer

January 7, 2019, 12:00 am
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Finding out number of 5's in 20! Will give us 4.
And as 20! Is given twice we take 4+4=8.
Hence, B.

Why we look for 5 and not 2?
→ because there will always be a greater no of 2's so we look for exact number of 5's to know the perfect answer.

Posted from my mobile device
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Data Sufficiency (DS) | Re: A list contains n distinct integers. Are all n integers cons

January 7, 2019, 12:00 am
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futurephilantropist wrote:

Hello,
I have a question:
For Statement 1:
if we take consecutive even numbers {2,4,6}:
When lowest number is removed, set becomes {4,6} - the average 5
When the highest number is removed, set becomes {2,4} - the average is 3.
Why above presented can not prove statement 1 as insufficient?


Hi futurephilantropist,

TESTing VALUES is a great way to approach this question, but you have to choose values that 'fit' the given information. The information in Fact 1 tells us that the difference in
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Data Sufficiency (DS) | Re: Two dressmakers, Sue and Anne, sewed costumes for a local theater prod

January 7, 2019, 12:00 am
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Data Sufficiency (DS) | Re: If Tom and Huckleberry working at their respective rates can each whit

January 7, 2019, 12:00 am
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Problem Solving (PS) | Re: If p, q are different prime numbers greater than 2, which of the follo

January 7, 2019, 12:00 am
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philipssonicare wrote:

If p, q are different prime numbers greater than 2, which of the following can have at most 3 different factors?

A) \(2p+q\)
B) \(p+q\)
C) \(pq\)
D) \(p^2q\)
E) \(p^q\)



can you please explain?
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PS Archive | Re: Last year Manfred received 26 paychecks. Each of his first 6

January 7, 2019, 12:00 am
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Problem Solving (PS) | Re: Each Machine of type A has 3 steel parts and 2 chrome parts.

January 7, 2019, 12:00 am
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tonebeeze wrote:

Each Machine of type A has 3 steel parts and 2 chrome parts. Each machine of type B has 4 steel parts and 7 chrome parts. If a certain group of type A and type B machines has a total of 20 steel parts and 22 chrome parts, how many machines are in the group

A. 2
B. 3
C. 4
D. 6
E. 9


Let there be a type A machines and b type B machines:
Need: a+b

3a + 4b = 20
2a + 7b = 22

Solving those 2 equations: a=4, b=2
Therefore: 6
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