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Problem Solving (PS) | Re: A class of 40 students is to be divided into smaller groups. If each

January 7, 2019, 12:00 am
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Bunuel wrote:

A class of 40 students is to be divided into smaller groups. If each group is to contain 3, 4, or 5 people, what is the largest number of groups possible?

A. 8
B. 10
C. 12
D. 13
E. 14



12 groups of 3 and 1 group of 4

total 13 max possible

IMO D
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Problem Solving (PS) | Re: If x^2 - 2x - 15 = 0 and x > 0, which of the following must

January 7, 2019, 12:00 am
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Factor x2−2x−15=0 --> (x−5)(x+3)=0 --> x=5 or x=−3. Since given that x>0, then x=5 only.

Now, substitute x=5 into the options to see which one equals to 0.

Only II and III give 0.

Answer: D.
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Problem Solving (PS) | Re: 39,897*0.0096/198.76 is approximately

January 7, 2019, 12:00 am
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remove decimal part and do simple calculation. you will get correct answer.
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Problem Solving (PS) | Re: A builder purchases 25 windows at 25 percent off the total price of $1

January 7, 2019, 12:00 am
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Total cost of 25 windows= (75% of 1200)-75= 825

Cost of 1 window= 825/25 = 33 Ans

[size=80][b][i]Posted from my mobile device[/i][/b][/size]
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Data Sufficiency (DS) | Re: Is x a positive integer? (1) x > 0 (2) x^2 + 16 = 25

January 7, 2019, 12:00 am
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Skn1608 wrote:

Is x a positive integer?

(1) x > 0

(2) x^2 + 16 = 25

Spoiler: ::
the original answer is C.

I'm confused why the answer is not A. I know that zero is define as neither negative or positive, but based on the inequality symbol, the zero (0) should not be included?

That's why I thought statement (1) alone is sufficient.


Please expert help.

Thanks in advance



Statement 1. x>0

Option 1. If 'x' is an integer statement sufficient
Option 2. If 'x' is a fractional number 1/2,
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Problem Solving (PS) | Re: Doris spent 2/3 of her savings on a used car, and she spent 1/4 of her

January 7, 2019, 12:00 am
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Let the savings be"X".

\(\frac{2}{3}\) x is spent on used car.\(\frac{1}{4}\) of remaining is\(\frac{1}{3}*\frac{1}{4}*x\) =\(\frac{1}{12}*x\)

\(\frac{1}{12}*x\) = $250
x = $3000

OPTION:E
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Data Sufficiency (DS) | What is the value of a positive integer x? (1) x is three times the

January 7, 2019, 12:00 am
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Archit3110 wrote:

anshkool4u wrote:
Answer is A.
From stmnt 1,we know X=3*( sum of digits of X)
Now,supposing X is A3 digit no.,999,sum of digits =27,and 3 times 27= 81,a 2 digit no.which is contradictory in itself.
Considering X=100,sum of digits=1,hence 3 times 1=1,a one digit no.
This means X should be a 2 digit no.
Let X=10a+b
Then 10a+b= 3*(a+b)
Or 7a=2b,or a=3.5b.
Now,for the 2 digit no.X,a and b should both be integers,and should be 0<a,b<=9.
Only digits satisfying this are 2 and
)
Sufficient.

Stmnt
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Problem Solving (PS) | Re: The total fare for 2 adults and 3 children on an excursion boat is $14

January 7, 2019, 12:00 am
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Bunuel wrote:

The total fare for 2 adults and 3 children on an excursion boat is $14.00. If each child’s fare is one half of each adult’s fare, what is the adult fare?

A. $2.00
B. $3.00
C. $3.50
D. $4.00
E. $4.50



2x+3y=14
y=x/2
x=2y

4y+3y=14
y=2
x=4
IMO D
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Problem Solving (PS) | Re: The function f(x,y) is defined by the equation f(x,y)=x^3−5xy^2. If

January 7, 2019, 12:00 am
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Problem Solving (PS) | Re: A lighthouse blinks regularly 5 times a minute. A neighboring lighthou

January 7, 2019, 12:00 am
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generis wrote:

Bunuel wrote:
A lighthouse blinks regularly 5 times a minute. A neighboring lighthouse blinks regularly 4 times a minute. If they blink simultaneously, after how many seconds will they blink together again?

A. 20
B. 24
C. 30
D. 60
E. 300

Assume that they both blink at 0 seconds. The number of seconds after which they blink together again will be the same because the rates are fixed after the first blink.

Lighthouse #1 blinks 5 timesper minute
1 minute = 60 seconds
\( \frac{60}{5} =12 \)
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Problem Solving (PS) | Re: In a certain sequence, the term xn is given by the formula

January 7, 2019, 12:00 am
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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Problem Solving (PS) | Re: There are enough peanuts in a bag to give 12 peanuts to each of 20 chi

January 7, 2019, 12:00 am
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Bunuel wrote:

There are enough peanuts in a bag to give 12 peanuts to each of 20 children, with no peanuts left over. If 5 children do not want any peanuts, how many peanuts can be given to each of the others?

A. 12
B. 15
C. 16
D. 18
E. 20


If there are 12 peanuts to give to each of 20 children
=> Total peanuts =240

Children who dont want any peanuts =5

Now children who will get peanuts = 15

15 children now can get 240/15 = 16 peanut each.

IMO
Correct Answer C.
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Problem Solving (PS) | Re: Gheri is n years old. Carl is 6 years younger than Gheri and 2 years

January 7, 2019, 12:00 am
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Bunuel wrote:

Gheri is n years old. Carl is 6 years younger than Gheri and 2 years older than Jean. What is the sum of the ages of all three?

A. 3n + 16
B. 3n + 4
C. 3n − 4
D. 3n − 8
E. 3n − 14


Its Given, Gheri = n years old
Carl = n - 6

Carl = J +2
=> J = Carl-2
=> J = n-8

Sum of all three ages = n + n-6 + n-8 = 3n -14

Correct Answer E.
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Problem Solving (PS) | At a certain photography store, it costs Pete $1.65 for the first prin

January 7, 2019, 12:00 am
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At a certain photography store, it costs Pete $1.65 for the first print and $0.85 for each additional print. How many prints of a particular photograph can Pete get for $20.00?

A. 19
B. 20
C. 21
D. 22
E. 23
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Problem Solving (PS) | If (20!*20!)/20^n is an integer

January 7, 2019, 12:00 am
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If (20!*20!)/20^n is an integer, what is the largest possible value of n?

A. 6
B. 8
C. 10
D. 11
E. 12
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Problem Solving (PS) | Re: At the start of his 3 years graduation program Mr. John bought a car a

January 7, 2019, 12:00 am
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akurathi12 wrote:

At the start of his 3 years graduation program Mr. John bought a car at the market price of $x and sold it to Mr.Max at the end of 3rd year at the market price of $y.If the market price of car depreciated by 20%, 50/3% and 25% respectively in 3 consecutive years, which of the following is true?

A. 3x-2y=0
B. 2x=y
C. x+y=3y
D. 4x-3y=3x
E. None of these


After brain storming over this question for 3 mins, I will substitute values for for x and y
A. 3x-2y=0 => 3x=2y
B. 2x=y => This case is
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Problem Solving (PS) | Re: There are enough peanuts in a bag to give 12 peanuts to each of 20 chi

January 7, 2019, 12:00 am
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There are enough peanuts in a bag to give 12 peanuts to each of 20 children, with no peanuts left over.
Total Peanuts in the bag = 12 x 20 = 240

If 5 children do not want any peanuts, = 12 x 5 = 60 Peanuts left

how many peanuts can be given to each of the others?
Remaining are 15 Children, so 60/15 = 4 Peanuts per child in addition to 12.
Total of 12+4 = 16

Correct Answer is C
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Problem Solving (PS) | At the start of his 3 years graduation program Mr. John bought a car a

January 7, 2019, 12:00 am
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the awkward part is to translate this : 50/3 % =\((\frac{50}{3})/100 = \frac{50}{300}\)

\(x * (\frac{100}{100}-\frac{20}{100})(\frac{300}{300}-\frac{50}{300})(\frac{100}{100}-\frac{25}{100}) = y\)
\(x * \frac{4}{5}*\frac{5}{6}*\frac{3}{4} = y\)
\(x * \frac{1}{2} = y\)
\(x = 2y\)
\(x + y = 3y\)
so C
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Problem Solving (PS) | Re: Two cars travel away from each other in opposite directions at 24 mile

January 7, 2019, 12:00 am
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Bunuel wrote:

Two cars travel away from each other in opposite directions at 24 miles per hour and 40 miles per hour respectively. If the first car travels for 20 minutes and the second car for 45 minutes, how many miles apart will they be at the end of their trips?

A. 22
B. 24
C. 30
D. 38
E. 42


1st Car Speed : 24 miles per hour ; Travels for 20 minutes (1/3 of an hour)==> 24/3 = 8 miles Traveled
2nd Car Speed : 40 miles per hour ; Travels for 45 minutes (3/4 of an hour)==> 40x3/4 = 30 miles Traveled
They
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Problem Solving (PS) | Re: Three members of a family Raina, Mike and Peter were born on the same

January 7, 2019, 12:00 am
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akurathi12 wrote:

Three members of a family Raina, Mike and Peter were born on the same date in different years. This year on their birthday, the ages of Raina, Mike and Peter will form a geometric progression series, not necessarily in the same order. Raina is 4 times as old as Peter whereas Peter is the youngest amongst the three. Which of the following must be true?

I. Mike is 16 times as old as Peter.
II. Raina is the eldest
III. Sum of the ages of all three members is atleast 7.

A. I only
B. I&II only
C.

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