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GMAT Data Sufficiency (DS) | Re: ax + by=10, ay + bx=12. which one is greater here, x or y ?

August 8, 2013, 1:00 am
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AbhiJ wrote:

ax + by = 10
bx + ay = 12
Solvingforx andy wehave

x = (12b-10a)/(b^2-a^2)
y = (10b- 12a)/(b^2-a^2)

Since the question stem saysx > y we do the same and try to find the relation betweena andb.

(12b-10a)/(b^2-a^2) > (10b- 12a)/(b^2-a^2)

We get(b+a)/[(b+a)(b-a)] > 0 ------------(I)

From I we cannot cancel(b+a) from numerator and denominator unless weknow(b+ a) =! 0 , since the question doesnot

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GMAT Data Sufficiency (DS) | Re: Is a

August 8, 2013, 1:00 am
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kumar23badgujar wrote:

Consider,

Statement (1):a^3 < a^2 + 2a

a^3 - a^2 - 2a < 0
a(a^2 - a - 2) < 0
a(a -2)(a + 1) < 0

i.e. a = 0 or a = 2 or a = -1, hence not sufficient.

Statement (2):a^2 > a^3
This simply means,
a < 1, hence not sufficient.

Combining both statements, we geta = 0 or a = -1 , Hence both statements together notsufficient.

Correct Ans: E

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GMAT Data Sufficiency (DS) | Re: ax + by=10, ay + bx=12. which one is greater here, x or y ?

August 9, 2013, 1:00 am
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mau5 wrote:

AbhiJ wrote:
ax + by = 10
bx + ay = 12
Solvingforx andy wehave

x = (12b-10a)/(b^2-a^2)
y = (10b- 12a)/(b^2-a^2)

Since the question stem saysx > y we do the same and try to find the relation betweena andb.

(12b-10a)/(b^2-a^2) > (10b- 12a)/(b^2-a^2)

We get(b+a)/[(b+a)(b-a)] > 0 ------------(I)

From I we cannot cancel(b+a) from numerator and denominator unless weknow(b+ a) =! 0 , since the question doesnot mention

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GMAT Data Sufficiency (DS) | Re: Of the four numbers represented on the number line above, is

August 9, 2013, 1:00 am
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lucasITA wrote:

the question is not very clear for me.. i've chosen option E because i put ANY value for each letter, should not the question specify that the relation q<r <s <t has always to be true?


The question says "Of the four numbers represented on the number line above", so the order is what you get by looking at it: q<r <s <t.
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GMAT Problem Solving (PS) | Re: A man chooses an outfit from 3 different shirts, 2 different

August 9, 2013, 1:00 am
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itikakulkarni wrote:

I get the Numerator part - Probable outcomes. Cannot figure out about the denominator - Possible outcomes. (referring to August 2008 post by Kassalmd) Can someone help?


The denominator must represent the total number of combinations, according to the formula P=favorableOutcome/TotalOutcomes.

He can choose from 3 different shirts, 2 different pairs of shoes, and 3 different pants each day.

So the total number of outfits with the shirts is 3*3*3 (each day 3 possibilities), the total number of
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GMAT Problem Solving (PS) | Re: fraction

August 9, 2013, 1:00 am
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This a application of compound interest formula.

A = X [ 1 - Rate/100 ]^n (for decreasing rate.) note : A = X [ 1 + Rate/100 ]^n (for increasing rate.)

rate is 50%
n=5

Remaining leaves = X [1 - 50/100] ^5

= X/32 leaves remaining.

X - X/32 = 31/32 is lost fraction.
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GMAT Problem Solving (PS) | A and B in turns, throw a dice. If A gets a sum of 8 before

August 9, 2013, 1:00 am
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A and B in turns, throw a dice. If A gets a sum of 8 before B gets a sum of 9, then A wins. But if B gets a sum on 9 before A gets a sum of 8, then B wins. Find the chances of winning of A.

A. 31/36
B. 31/76
C. 5/36
D. 45/76
E. 1/9
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GMAT Problem Solving (PS) | Re: TIME AND SPEED QUESTION

August 9, 2013, 1:00 am
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Ahhhh! Because they both do it in the same time, we set (% of distance/rate) = (to be solved for distance/rate) This makes much more sense now. Thanks! Image



VeritasPrepKarishma wrote:

WholeLottaLove wrote:
ChrisLele wrote:
Think of it this way: if we wanted the two to finish at the same time, we would give B would only run 13/20 of the race, or the inverse of 20/13 (20/13 x 13/20 = 1, meaning they finish at the same time).

B finishes 20% ahead of A, so we take the 13/20 and we multiply

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GMAT Club Tests | Re: Probability Question (m05q31)

August 9, 2013, 1:00 am
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Zarrolou wrote:

hsb91 wrote:
By combinations, total possibilities = 8c2 = 28
NO Tulip -- 6c2 = 15
Thus, prob of no tulip = 15/28

For same case, using probability = 6/8* 5/7 = 15/28

When 1 tulip = 2c1* 6c1 = 2*6 = 12 .... NOT 24( i.e. only selections and not arrangements or order does not matter TNT is same as NT T )
Thus, Prob. = 12/28
For same case, Using prob = 2/8* 6/7 =6/28

Why we have to multiply with 2 when using prob. and no multiplication with 2 when using combinations ?

I hope you are getting what

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GMAT Problem Solving (PS) | Re: In a 200 member association consisting of men and women

August 9, 2013, 1:00 am
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Total numbers = 200. Men = X, Women = Y.
We are told that exactly 20% of men are homeowner => X is a multiple of 5 => X=5a (a>=1). Similarly, Y = 4b (b>=1). Find min(a+b)

X + Y = 200 <=> 5a + 4b = 200. a and b are all integers.
When a = 36, b=5 => (a+b)--->min.

E.
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GMAT Problem Solving (PS) | Re: If n is an integer and 1/(n+1)

August 9, 2013, 1:00 am
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1/n> 1/31+1/32+1/33> 1/33+ 1/33 + 1/33 = 3/33 = 1/11 ====> n<11

1/(n+1)< 1/31 + 1/32+ 1/33 < 1/31 + 1/31 + 1/31 = 3/31 ====> n>9,3

Then, n=10.

B.
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Integrated Reasoning (IR) | Re: Loan X has a principal of $10,000x and a yearly simple inter

August 9, 2013, 1:00 am
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ksung84 wrote:

Loan X has a principal of $10,000x and a yearly simple interest rate of 4%. Loan Y has a principal of $10,000y and a yearly simple interest rate of 8%. Loans X and Y will be consolidated to form Loan Z with a principal of $(10,000x + 10,000y) and a yearly simple interest rate of r%, where r = (4x+8y)/(x+y). In the table, select a value for x and a value for y corresponding to a yearly simple interest rate of 5% for the consolidated loan. Make only two selections, one in each column.

..........

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GMAT Data Sufficiency (DS) | Re: If M=P*Q, where P and Q are different positive integers,

August 9, 2013, 1:00 am
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GMAT Club Tests | Extending GMAT Club Test Past 3 months

August 9, 2013, 1:00 am
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BB,

Can I extend my GMAT Club Tests with Kudos? When I tried to access my tests, the system was saying the subscription expired but doesn't let me extend with 25 kudos.

Please help

NT2010
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GMAT Problem Solving (PS) | Re: Two buses are travelling on the highway from X to Y .

August 9, 2013, 1:00 am
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guerrero25 wrote:

Two buses are travelling on the highway from X to Y . The speed of the first bus is 60KMPH and the second bus travels at the speed of 40KMPH. The first bus leaves at 11 AM and the second leaves 15 mins later. The first bus starts back for X, 15 mins after it reaches Y . How far from Y will the first Bus meet the second ?Also, after how much time will they meet each other after the departure of the first bus from X , if the distance between X and Y is 180 KM.

A)36 KM , 3 Hrs 36 Mins
B)36 KM, 3

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GMAT Problem Solving (PS) | Re: 4 baseball players each stand at different corners of a base

August 9, 2013, 1:00 am
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gmatpapa wrote:

4 baseball players each stand at different corners of a baseball diamond. The sides of the diamond are all of equal length. Two arrangements of baseball players are considered different only when the relative positions of the players differ. How many different ways can the baseball players arrange themselves around the diamond?

A. 4
B. 6
C. 16
D. 24
E. 256

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for circular permutation, just minus 1 and permute.
so 3! = 6 ways
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GMAT Problem Solving (PS) | Re: Rachel has ribbons that are blue, green, red, orange, and ye

August 9, 2013, 1:00 am
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gmatpapa wrote:

Rachel has ribbons that are blue, green, red, orange, and yellow. To identify the plants in her garden, she ties either 1 ribbon, or 2 ribbons of different colors, to each plant. How many different plants can Rachel label in this way without labeling more than one plant the same way?

A. 5
B. 10
C. 15
D. 20
E. 25

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solution:
using only one in each plant = 5C1 = 5
using two ribbons in each plant = 5C2 = 10 (different colors is the topic here not their arrangement, so combination).

total
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GMAT Problem Solving (PS) | Re: There are trains travelling on 4 parallel tracks. The freque

August 9, 2013, 1:00 am
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guerrero25 wrote:

There are trains travelling on 4 parallel tracks. The frequencies of trains traveling on these tracks at equal interval of time are 4, 6, 8, 12 per hour respectively. If all trains start at 7 AM, after how much time will all the trains start together from the same place?

A. 1 Hour
B. 12 Hours
C. 24 Hours
D. 1/2 hours
E. 1/4 Hours

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after leaving,
the schedule(min) of 2nd train for 4lines= 15min 10min 7.5min 5min
LCM = 30 mins . so 1/2 hour(D)
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GMAT Problem Solving (PS) | Re: Stephanie, Regine, and Brian ran a 20 mile race. Stephanie

August 9, 2013, 1:00 am
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Stephanie, Regine, and Brian ran a 20 mile race. Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours. If nobody ran faster than 8 miles per hour, who could have won the race?

I. Stephanie
II. Regine
III. Brian

Time (s) + time (r) = time (b) +2

d=20

If no one ran faster than 8 miles/hour than no one completed the race in under 2.5 hours (time = distance/rate ===> time = 20/8 ===> time = 2.5 hours)

If S+R = B+2, Brian's time will always be greater than
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Integrated Reasoning (IR) | Re: For each of the following statements, select True if the

August 9, 2013, 1:00 am
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