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Problem Solving (PS) | Re: If R is the set of all numbers that, when squared, have a units digit

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Problem Solving (PS) | Re: 12:00 am, Mary passed a certain gas station on a highway while traveli

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Shrinking gap kind of problem here...
relative speed = 3r/2 - r = 1/2 r
in 1 hour Mary does r miles -- so the distance between her and Paul is r miles.

to find time when they catch up: r mile / (r/2) = 2

so Paul will catch up with mary in 2 * (3r/2) = 3 r

Problem Solving (PS) | Re: 1^1+2^2+3^3+...+10^10 is divided by 5. What is the

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PS Archive | 1^1+2^2+3^3+...+10^10 is divided by 5. What is the

Problem Solving (PS) | Re: If k and n are positive integers such that n > k, then k! + (n-k)*(k-1

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Problem Solving (PS) | Re: when W is divided by 14, the reminder is 0. if W is three lesser than

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anik1989 wrote:

when W is divided by 14, the reminder is 0. if W is three lesser than it value and when divided by 15 its remainder is 14. what is the value of W ?

a. 182
b.282
c. 382
d.482
e. 582

is there any method to calculate directly rather than putting each choice??


Hello Experts,

If w = 14k which means w is a multiple of 14 and it has to contain 2 and 7 atleast or it has to be divisible by 2 and 7 both. If we scan the answer choices we can see that all five options are divisible by 2 since the units
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Data Sufficiency (DS) | Re: What is the value of abcd+a+b+c+d ?

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Problem Solving (PS) | Re: What is the greatest positive integer which will divide 3962, 4085 and

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shivamagarwal wrote:

Solenja wrote:
Explanation:

We have to find Greatest Factor

In this case , we have to find HCF with remainder

Step 1: Find the Differences of numbers

Step 2: Get the HCF ( that differences)

We have here 3962, 4085 and 4167

So differences are

4167 - 4085 = 82


4167 - 3962 = 205,

4085 - 3962 = 123.

Now

HCF (82, 123 and 205)

As

82 = 2 x 41

123 = 3 x 41

205 = 5 x 41

HCF = 41.

And 41 is the requirednumber.(source:internet)




Hello Expert,

What is the reason or logic behind
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Problem Solving (PS) | Re: A certain company charges $6 per package to ship packages weighing les

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EducationAisle wrote:

Kimberly77 wrote:
If the question had been $2 per additional pound, will it be 6 + 2(n-1) = 38 ? Thanks for your time inadvanced.

Shouldn't the equationbe:

6 +2(n-2 ) =38


Ah my bad Image thanksEducationAisle for your reply and yes it should be n-2 here since is $2 per additional pound. My main point is to confirm the equation format is right and thanks for your
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Problem Solving (PS) | Re: If the given Quadrilateral is a rectangle, find the area of the shaded

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Problem Solving (PS) | Re: From a group of 3 boys and 3 girls, 4 children are to be

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Problem Solving (PS) | Re: If set S consists of 5 consecutive integers and the average of set S

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Bunuel wrote:

If set S consists of 5 consecutive integers and the average of set S is x, which of the following must be true?

I. x is an integer
II. x is the median of set S
III. The difference between x and the largest number in set S is equal to the difference between x and the smallest number in set S.

(A) II only
(B) III only
(C) I and III
(D) II and III
(E) I, II, andIII


a-2, a-1, a, a+1, a+2
S = x = a

I. Since a is an integer and x = a, x is an integer. A, B, and D are out. We do not need to check
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Problem Solving (PS) | Positive integer p is 16 percent of 16 percent of positive integer q,

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Bunuel wrote:

Positive integer p is 16 percent of 16 percent of positive integer q, and p percent of q equals 16. What is the value of q ?

(A) 125
(B) 160
(C) 240
(D) 250
(E)4,000


\( p =0.16*0.16*q\)

\(\frac{p}{100} *q =16\)

\( pq =1600\)

\( p =\frac{1600}{q}\)

\( 0.16*0.16*q =\frac{1600}{q}\)

\( (0.16)^2*q^2 =40^2\)

\( q^2 =\frac{40^2}{(0.16)^2}\)

\( q =\frac{40}{0.16} =\frac{4000}{16} =\frac{1000}{4} =250\)

Answer choice D.
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Problem Solving (PS) | Re: What is the number of odd integers that are greater than 116,999 and

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Bunuel wrote:

What is the number of odd integers that are greater than 116,999 and less than 117,289?

(A) 147
(B) 146
(C) 145
(D) 144
(E) 143


117001
...
117287

That's the same thing as
1
...
287

Each item in the list is entry number (n+1)/2 in the list.
287 is (287+1)/2 = 288/2 = 144.

Answer choice D.

Problem Solving (PS) | Re: In how many ways can 4 boys and 4 girls be arranged in a row such that

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Problem Solving (PS) | Re: The number m yields a remainder p when divided by 14 and a remainder q

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Problem Solving (PS) | The perimeter of the square ABCD is 8 meters. Another square, abcd, is

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The perimeter of the square ABCD is 8 meters. Another square, abcd, is inscribed in ABCD. What is value of the perimeter of abcd, in meters?

(A) 4
(B) 4.5
(C) 5
(D) 5.5
(E) 6

Data Sufficiency (DS) | Re: In JKL shown above, what is the length of segment JL ?

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Jatin108 wrote:

Hi everyone, i just had one doubt cant 30-60-90 has two different lengths :
like 6,8,10 ( which is 3,4,5 - 30-60-90 triangle) and also 5,5sqrt(3),10 ( 1:sqrt(3):2) ratio)
so in that case 10 Can lead to two difftriangles


Hi Jatin108,

A 30/60/90 right triangle has a 'fixed' relationship in terms of the lengths of the three sides (the specific 'ratio of sides' is X : X√3 : 2X). By extension, if we know the length of any one of the sides in a 30/60/90 right triangle, then we can determine the
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Problem Solving (PS) | Re: In how many ways can Seven faces of a Pentagonal prism be painted with

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hD13 wrote:

In how many ways can Seven faces of a Pentagonal prism be painted with seven different colors

A. 720
B. 5040
C. 144
D. 504
E. 360

Posted from my mobile device




Why is it not 7! ??

Problem Solving (PS) | Re: For a certain race, 3 teams were allowed to enter 3 members each.

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JohnMuchiri wrote:

I think a simple solution for the question would be:
Since the number of games to be played is 3, that is each group to give one of its members. It means.

The least position that a member could be is number 5. i.e In a number of points is 6- n hence 6-5 = 1X(3 games for the three players) =3


Hi JohnMuchiri,

What you describe does NOT match-up with the information given in the prompt. To start, there is just ONE race - with three teams of three individual people (re: 9 total people) racing in
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