Bunuel wrote:
Four integers have a mean (arithmetic average) of 36. Three of the integers are 6, 30, and 64. If the fourth integer is 2K, then K =
(A) 20
(B) 22
(C) 24
(D) 40
(E) 44
6 + 30 + 64 + 2k = 36*4
Or, 100 + 2k = 144
So, 2k = 44
Or, k = 22, answer must be (B)










