That is the problem. I also marked letter (D). I think that official answer (E) is wrong.
Let Failure = x, so Success= x/9. Since S+F=1 --> x + x/9
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Hero8888 wrote:
CursoFDX wrote:
The probability of success in a field event is the ninth part of the probability of failure. Successive and independent trials are held until success occurs for the first time. In these circumstances, the expected number of failures that should occur until the first success occurs is equal to:
(A) 2
(B) 3
(C) 6
(D) 9
(E) 10
(A) 2
(B) 3
(C) 6
(D) 9
(E) 10
Let Failure = x, so Success= x/9. Since S+F=1 --> x + x/9
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