Four integers have a mean (arithmetic average) of 36. Three of the integers are 6, 30, and 64. If the fourth integer is 2K, then K =
(A) 20
(B) 22
(C) 24
(D) 40
(E) 44
Arithmetic Mean(AM) = Sum/No. of terms
Sum= 6+30+64+2K = 100 +2K
No. of terms = 4
AM= 36 = (100 +2k)/4
144 = 100+2k
44=2k
22=k
Correct Answer= B
(A) 20
(B) 22
(C) 24
(D) 40
(E) 44
Arithmetic Mean(AM) = Sum/No. of terms
Sum= 6+30+64+2K = 100 +2K
No. of terms = 4
AM= 36 = (100 +2k)/4
144 = 100+2k
44=2k
22=k
Correct Answer= B
