Given: BD = 10 | AC = 15 | CE = 30
From the above figure, we are given Angle C = D = 90. Angle E is common.
Hence, the triangles ACE and BDE are similar(AAA similarity)
In similar triangles, the ratios of the length of the corresponding sides are equal.
\(\frac{BD}{DE} = \frac{AC}{CE}\)
Substituting values
\(\frac{10}{x} = \frac{15}{30}\) ->\(x = 10*2 = 20\)
Therefore, the length of CD = CE-DE = 30-20 =10(Option A)
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