benejo wrote:
10 years ago, Jack was twice as old a Renee. Two years from now, Jack will be 1.5 time as old as Renee. What was the sum of the ages of Jack and Renee 5 years ago?
A. 28
B. 36
C. 46
D. 50
E. 56
Source: ExpersGlobal
Solve the first two equations. "Five years ago" can be handled at the end.
Ten years ago, Jack was twice as old as Renee:
J - 10 = 2(R -10)
J - 10 = 2R - 20
J = 2R - 10
Two years from now, Jack will be 1.5 times as old as Renee.
J + 2 = \(\frac{3}{2}\)
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