fluke wrote:
Is |x – 3| > |y – 3|?
x-3 > -(y-3)
x-3 > -y+3
x+y > 6
or
x-3 > y-3
x-y > 0
x>y
so; if x>y and x+y>6; we can be sure that |x-3| > |y-3|
(1)x > y.
But we don't know whether x+y>6. Not sufficient.
x=2
y=1
1<2
x=5
y=2
2>1
(2)xу is not equal to 0.
We don't know whether x>y or x+y>6. Not sufficient.
Same sample set from 1 can be used;
Together;
We don't know whether x+y>6. Not sufficient.
Same sample set from 1 can be used.
Ans: "E"
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