Bunuel wrote:
How many different arrangements to seat four spectators in four of seven empty stadium seats that are all in the same row are possible?
(A) 12
(B) 24
(C) 28
(D) 35
(E) 840
Since there are 7 empty seats and we need to seat four spectators in four of
the empty stadium seats, there are 7 ways of seating the first spectator.
There are 6,5, and 4 ways of seating the other 3 spectators.
Therefore, there are 7*6*5*4 = 42*20 =840 ways(Option E) of seating the 4 spectators
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