grgsky wrote:
ScottTargetTestPrep wrote:
Bunuel wrote:
If d = (c - b)/(a - b), then b =
A. (c - d)/(a - d)
B. (c + d)/(a + d)
C. (ca - d)/(ca + d)
D. (c - ad)/(1 - d)
E. (c + ad)/(d -1)
A. (c - d)/(a - d)
B. (c + d)/(a + d)
C. (ca - d)/(ca + d)
D. (c - ad)/(1 - d)
E. (c + ad)/(d -1)
First, we multiply both sides by (a - b) and expand the left side:
d(a - b) = c - b
da - db = c - b
Now, since our goal is to solve for b, we put all terms containing b on the left side of the equation and all other terms on the right side:
b - db = c - da
On the left side of the equation, factor out the common factor b from both terms:
b(1 - d) = c - da
Divide
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