Bunuel wrote:
calreg11 wrote:
S and T are two-digit positive integers that have the same digits but in reverse order. If the positive difference between S and T is less than 40, what is the greatest possible value of S minus T?
A. 27
B. 30
C. 33
D. 36
E. 39
A. 27
B. 30
C. 33
D. 36
E. 39
Two-digit integerab can be expressed as 10a+b, for example: 45=10*4+5.
Given: S-T=(10a+b)-(10b+a)=9(a-b)<40 --> greatest multiple of 9 which is less than 40 is 36. For example S can be 51 and T can be 15.
Answer: D.
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