Nived wrote:
Please suggest where I have gone wrong.
n^2 100
So, I am getting C, while right answer is A.
HiNived
kindly read the question correctly. the question asks you to find the reciprocal of\(n\) and not of\(n^2\)
what you have got here is the reciprocal of\(n^2\) which is incorrect.
so you have\(\frac{1}{n^2}>100 =>\frac{1}{n^2}-10^2>0\)
\(=>(\frac{1}{n}-10)(\frac{1}{n}+10)>0\)
so you have either\(\frac{1}{n}>10\) or\(\frac{1}{n}<-10\) . Now since\(n\) is towards the left of\(0\) , i.e. negative so\( \frac{1}{n} >10 \)
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