ttaiwo wrote:
Hi Bunuel,
I understand how If g(x)=x^2 ... g(n+12) will thus be g(n+12)^2
However, I don't understand how if f(x)=2x-1 ... f(n^2) would be 2n^2-1 ... I thought it would be (2n-1)^2...why is this wrong?
Thanks.
Tosin
\(f(x) = 2x - 1\) . To get\(f(n^2)\) put n^2 instead of x: \(f(n^2)=2n^2-1\).
\(g(x) = x^2\) . To get\(g(n+12)\) put n + 12 instead of x:\(g(n+12)=(n+12)^2=n^2+24n+144\) .
...
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