Bunuel wrote:
ttaiwo wrote:
Hi Bunuel,
Thanks for the factoring link...I was having problems factoring quadratics where a was greater than 1.
Anyhow...with my newfound knowledge I attempted this particular question and still came unstuck at one final stage...
Yes I understand that (x-3) (2x-3)<0 ... I then did the following:
x-3<0 ... so x<3
2x-3<0 ... so 2x<3...x<1.5
How can x be less than 3 and less than 1.5 and thus be an integer 2?
I clearly went wrong somewhere
here.Thanks for the factoring link...I was having problems factoring quadratics where a was greater than 1.
Anyhow...with my newfound knowledge I attempted this particular question and still came unstuck at one final stage...
Yes I understand that (x-3) (2x-3)<0 ... I then did the following:
x-3<0 ... so x<3
2x-3<0 ... so 2x<3...x<1.5
How can x be less than 3 and less than 1.5 and thus be an integer 2?
I clearly went wrong somewhere
Thanks,
Tosin
(x - 3)(2x
...








