Bunuel wrote:
If the sum of the square roots of two integers is \(\sqrt{9+6\sqrt{2}}\), what is the sum of the squares of these two integers?
(A) 40
(B) 43
(C) 45
(D) 48
(C) 52
AnisMURR wrote:
Let a and b be both of the integers.
\(\sqrt{a}+\sqrt{b}=\sqrt{9+6\sqrt{2}}\)
Lets square both sides of the equation
weget
\(a+b+2\sqrt{a}\sqrt{b}=9+6\sqrt{2}\)
Then
\(a+b= 9\) [1]
\(2\sqrt{a}\sqrt{b}=6\sqrt{2}\) [2]
[2] \(\sqrt{ab}=3\sqrt{2}\) lets square both sides \(ab=18\)
so we get
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