Problem Solving (PS) | Re: If there are four distinct pairs of brothers and sisters

As committee shouldn't have siblings in it, then a pair can send only one "representative" to the committee. # of ways to choose which 3 pairs of brothers and sisters should send one "representative" to the committee is\(C^3_4\) (choosing 3 pairs which will be granted the right to send one "representative" to the committee);

Buteach of these 3 pairs can send 2 persons to the committee either a brother or a sister:\(2*2*2=2^3\) ;

So total # of ways is\(C^3_4*2^3=32\) .