Assuming that there's a circle subscribing the traingle ABC with center D and radious DA = DC= DB.
AC must be a diagonal hence, Angle ABC is a 90• and Traingle ABC is a right angled traingle. Now it's given that angle BAD is 50, so we can calculate Angle BCA (180-90-50 = 40•)
[size=80][b][i]Posted from my mobile device[/i][/b][/size]
AC must be a diagonal hence, Angle ABC is a 90• and Traingle ABC is a right angled traingle. Now it's given that angle BAD is 50, so we can calculate Angle BCA (180-90-50 = 40•)
[size=80][b][i]Posted from my mobile device[/i][/b][/size]








