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Problem Solving (PS) | Re: At time t measured in minutes after the beginning of the timed period,

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HG90 wrote:

animesh mohanty wrote:
For a difference of 30 mins the corresponding change in speed is 5, next we find that the change is proportional throughout ie t/6. so the speed of the train after time t is 40+ t/6 (D).

Pls. Note the time is in minutes nothours.

change of 5 mph =0.083 miles per min which is achieved in 30 mins. This is the same as change of 0.041 miles per min that is achived in 15 mins. so the logic is correct.
P.S. i didn't mark the difference initially. Thank!
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