SajjadAhmad wrote:
If x ≠ 0, \(\frac{x(x^5)^2}{x^4}\) =
(A) x^5
(B) x^6
(C) x^7
(D) x^8
(E) x^9
\(\frac{x(x^{5*2})}{x^4}=\frac{x^{10+1}}{x^4}\)
or \(x^{11-4}=x^7\)
Option C
If x ≠ 0, \(\frac{x(x^5)^2}{x^4}\) =
(A) x^5
(B) x^6
(C) x^7
(D) x^8
(E) x^9
\(\frac{x(x^{5*2})}{x^4}=\frac{x^{10+1}}{x^4}\)
or \(x^{11-4}=x^7\)
Option C
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