Engr2012 wrote:
anupamadw wrote:
Bunuel wrote:
Is |x| < 1 ?
Is |x| < 1 --> is -1 < x < 1.
(1) x/|x| < x.
Two cases:
A.\(x<0\) -->\(\frac{x}{-x}<x\) -->\(-1<x\) . Since we consider the case when\(x<0\) , then we'd have\(-1<x<0\) . Answer YES.
B.\(x>0\) -->\(\frac{x}{x}<x\) -->\(1<x\) . Answer NO.
Not sufficient.
(2) x/|x| < 1. This simply means that x is a negative number: if x is positive then x/|x| = 1, if x is negative x/|x| = -1 < 1. Not sufficient.
(1)+(2) Since from (2) we have that x is negative, then we have
Is |x| < 1 --> is -1 < x < 1.
(1) x/|x| < x.
Two cases:
A.\(x<0\) -->\(\frac{x}{-x}<x\) -->\(-1<x\) . Since we consider the case when\(x<0\) , then we'd have\(-1<x<0\) . Answer YES.
B.\(x>0\) -->\(\frac{x}{x}<x\) -->\(1<x\) . Answer NO.
Not sufficient.
(2) x/|x| < 1. This simply means that x is a negative number: if x is positive then x/|x| = 1, if x is negative x/|x| = -1 < 1. Not sufficient.
(1)+(2) Since from (2) we have that x is negative, then we have
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