Bunuel wrote:
If a square has a side of length s and a diagonal of length d, then s^2/d^2 =
(A) 1/4
(B) √2/4
(C) 1/2
(D) √2/2
(E) 2/1
Another way is to choose numbers.
Let\(s = 2\) , then\(d = s \sqrt{2}\) , so
\(d = 2\sqrt{2}\)
\(\frac{s^2}{d^2}\) =\(\frac{2^2}{(2\sqrt{2})^2}\) =\(\frac{4}{8} = \frac{1}{2}\)
Answer C
...
