Bunuel wrote:
If x is an integer, is \(\sqrt{3x - y} = \sqrt{2x - 2y}\) ?
(1) x^2 = y
(2) x^3 = y
\(\sqrt{3x - y} = \sqrt{2x - 2y}\) , square both sides toget
\(3x-y=2x-2y\) or the question becomes Is\(x=-y\) ?
Statement 1 implies that\(x=\sqrt{y}\) or\(-\sqrt{y}\) .\(x\) can be equal to\(-y\) in one situation; if\(y=1\) and\(x=-\sqrt{y}\) but if\(y\) has any other value then\(x\) will not be equal to\(-y\) . hence no unique value.Insufficient
Statement 2 \(x=y^\frac{1}{3}\) . Hence\(x\) is not equal to\(-y\) .Sufficient
IMOB
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