Problem Solving (PS) | Re: If y = |x – 1| and y = 3x + 3, then x must be between which of the

Bunuel ... this is how I approached this question. is it ok to do this way?

y=|x-1| so y=(x-1) or y=-(x-1)

First consider y=(x-1)
since y=3x+3 we have an equation 3x+3=x-1, solving this equation gives x=-2 which when plugged in the given equations does not hold. Plugging x=-2 in y=|x-1| gives y=3 and Plugging x=-2 in y=3x+3 gives y=-3 so x=-2 is not the desired solution.

Now consider y=-(x-1)
Using the same approach, we get x=-1/2 which when plugged in the given equations gives y=3/2 in