Problem Solving (PS) | If n is the product of 3 different prime numbers, how many factors doe

Let the 3 different prime numbers be a,b,and c.

If\(n = a^x*b^y*c^z\) where x,y, and z are the powers of the respective prime numbers
then the number "n" has\((x+1)(y+1)(z+1)\) factors .

In this case, x=y=z=1, the number n will have 2*2*2 or 8 factors.

Therefore, excluding 1 and n, the number
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