Bunuel wrote:
In the figure above, the large square is divided into two smaller squares and two shaded rectangles. If the perimeters of the two smaller squares are 8 and 20, what is the sum of the perimeters of the two shaded rectangles?
(A) 14
(B) 18
(C) 20
(D) 24
(E) 28
[Reveal] Spoiler:
The smallest square has perimeter = 8 = 4*side = 4a
i.e. side of the smallest square, a =\(2\)
The Second smallest square has
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