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Problem Solving (PS) | Re: xy and yx are reversed two digit positive integers. If the difference

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C. x and y are place holder values. Let the first number be A and the second number be B.

A = 10x+y, B= 10y+x

(for example 57 = 10(5) +7(1), 957 = 100(9)+10(5)+7(1))

A-B = 10x+y-(10y+x)

= 10x+y-10y-x

= 10x-x+y-10y

=9x-9y

We are told 9x-9y >10 and is a perfect square

9x-9y = 9(x-y)

= 3^2( x-y)


x-y must also be a perfect square. Of all the options given, only 4 is the perfect square.

9(x-y) = 9*4 = (3^2)(2^2)

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