MathRevolution wrote:
\((7^3)a+(7^2)b+7c+d=1045\), where a, b, c, and d are integers from 0 to 6, inclusively, b=?
A. 0
B. 1
C. 2
D. 3
E. 4
If we read this question carefully we see that it is just asking us to convert decimal 1045 or(1045)10 to a number in base 7 system...
(7^3)a+(7^2)b+7c+d=(7^3)a+(7^2)b+(7^1)c+(7^0)d
or (abcd) base 7= (1045) base 10
(abcd)7 (1045)10
This is done by calculating quotients of various powers of 7 involved in 1045;
So,
...
