This problem becomes a lot easier when we assume numbers.
If we were buying 1 unit fuel worth 100$ and the old car was
offering a mileage of 10 miles/gallon, it would cost us 10$ to drive a mile
Since the price has gone up by 20%, the fuel will now cost 120$.
If he needs to spend the same amount per miles driven,
Let the mileage of the new car be x
Therefore,\(\frac{120}{x} = 10\)
\(x = 12\) (which is a 20% increase over 10$/galon)(Option C)
...
If we were buying 1 unit fuel worth 100$ and the old car was
offering a mileage of 10 miles/gallon, it would cost us 10$ to drive a mile
Since the price has gone up by 20%, the fuel will now cost 120$.
If he needs to spend the same amount per miles driven,
Let the mileage of the new car be x
Therefore,\(\frac{120}{x} = 10\)
\(x = 12\) (which is a 20% increase over 10$/galon)(Option C)
...









