Data Sufficiency (DS) | If x≠0, is |x| < 1 ? (1) x^2< 1 (2) |x| < 1/x

Also if\(x<0\) then we have\(-x<\frac{1}{x}\) and now if we cross multiply by negative\(x\) then we should flip the sign:\(-x^2>1\) -->\(x^2+1<0\) which cannot be true for any real value of\(x\) (the sum of two positive value cannot be less than zero).