Problem Solving (PS) | Re: In triangle XYZ above, the length of XZ is 6/7 of the length of altitu

If the length of XZ is\(\frac{6}{7}\) the length of the altitude 'h', the base of the triangle(XZ) is\(\frac{6z}{7}\)

We know that area is\(\frac{1}{2}\) *Base*Height

Therefore, Area =\(\frac{1}{2}\) *\(\frac{6z}{7}\) z =\(\frac{3z^2}{7}\)(Option B)
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