Problem Solving (PS) | Re: In the figure, the areas of parallelograms EBFD and AECF are 3 and 2 r

This question looks difficult but it is very easy
let the height of the parallelogram be h no notice that we have to find the area of the rectangle .
That means both the given parallelogram are between parallel lines and their height will be same
So area of parallelogram EBFD =3 =a*h.......1
area of parallelogram AECF=2=b*h........2
Now notice the equations
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