Bunuel wrote:
\(\frac{[(n+3)!]^5}{[(n+2)!]^5} =\)
A. 2
B. (n+1)^5
C. (n+2)^5
D. (n+3)^5
E. ((n+3/(n+2))^5
\([\frac{(n+3)!}{(n+2)!}]^5=\)
(n+3)! = (n+3)(n+2)!
(n+3)!/(n+2)! = n+3
\([\frac{(n+3)!}{(n+2)!}]^5=\) = (n+3)^5
Answer D
\(\frac{[(n+3)!]^5}{[(n+2)!]^5} =\)
A. 2
B. (n+1)^5
C. (n+2)^5
D. (n+3)^5
E. ((n+3/(n+2))^5
\([\frac{(n+3)!}{(n+2)!}]^5=\)
(n+3)! = (n+3)(n+2)!
(n+3)!/(n+2)! = n+3
\([\frac{(n+3)!}{(n+2)!}]^5=\) = (n+3)^5
Answer D
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