Problem Solving (PS) | Re: Xavier, Yvonne, and Zelda each try independently to solve a

Hi Sash143,

The question does not state anything about what the "order" of the outcomes must be - just the probability of each of the individual outcomes (and the specific 'overall' outcome that we're looking to calculate). Thus, it's not a permutation question (meaning that it does NOT matter who attempts to solve the problem first, second or third) - and we don't have to do anything besides multiply the individual probabilities together to get the correct answer.

GMAT assassins aren't
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