Bunuel wrote:
SOLUTION
If the numbers 17/24, 1/2, 3/8, 3/4, and 9/16 were ordered from greatest to least, the middle number of the resulting sequence would be
(A) 17/24
(B) 1/2
(C) 3/8
(D) 3/4
(E) 9/16
The least common denominator for all the fractions above is48:
\(\frac{17}{24}=\frac{34}{48}\) ,\(\frac{1}{2}=\frac{24}{48}\) ,\(\frac{3}{8}=\frac{18}{48}\) ,\(\frac{3}{4}=\frac{36}{48}\) ,\(\frac{9}{16}=\frac{27}{47}\) .
The numerators in descending order are: 36, 34, 27, 24, 18. The middle number is 27, which corresponds to\(\frac{9}{16}=\frac{27}{47}\) .
Answer: E.
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