Venn Diagram is the way to go.
A= Only Spanish
B= Only French
C= Both
D= Neither
A+B+C+D=1
D=0.1 (stated)
Therefore A+B+C=0.9
A+B =0.7 (70% take only one language class)
A+B+C=0.9
A+B =0.7
Therefore C =0.2
C= 50 so therefore there are 250 students 50/0.2 (as C = 0.2 if C is 20% of the pie and is 50 then 100% of the pie is 250)
B+C=0.5 (stated, half the students take French)
Therefore B+C = 125 (250*0.5)
C=50 therefore B = 75 (125-50)
A+B =0.7
Therefore A+B =175 (250*0.7)
B=75 therefore A=100,
...
A= Only Spanish
B= Only French
C= Both
D= Neither
A+B+C+D=1
D=0.1 (stated)
Therefore A+B+C=0.9
A+B =0.7 (70% take only one language class)
A+B+C=0.9
A+B =0.7
Therefore C =0.2
C= 50 so therefore there are 250 students 50/0.2 (as C = 0.2 if C is 20% of the pie and is 50 then 100% of the pie is 250)
B+C=0.5 (stated, half the students take French)
Therefore B+C = 125 (250*0.5)
C=50 therefore B = 75 (125-50)
A+B =0.7
Therefore A+B =175 (250*0.7)
B=75 therefore A=100,
...








