Math mods and others - Please check my approach:
Given: n is less than 0, implying n is negative.
Also given:\(n^2\) <\(\frac{1}{100}\)
Square rooting both sides:
n< -\(\frac{1}{10}\) AND n <\(\frac{1}{10}\)
Reciprocating both the inequalities,
\(\frac{1}{n}\) <-10 AND \(\frac{1}{n}\) <10
Since,\(\frac{1}{n}\) MUST be less than -10 and 10 at all times, the option that always satisfies this is A.
Is this a right approach? I always falter when removing the squares on both sides of the equation/inequality and I want to make sure my approach is
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Given: n is less than 0, implying n is negative.
Also given:\(n^2\) <\(\frac{1}{100}\)
Square rooting both sides:
n< -\(\frac{1}{10}\) AND n <\(\frac{1}{10}\)
Reciprocating both the inequalities,
\(\frac{1}{n}\) <-10 AND \(\frac{1}{n}\) <10
Since,\(\frac{1}{n}\) MUST be less than -10 and 10 at all times, the option that always satisfies this is A.
Is this a right approach? I always falter when removing the squares on both sides of the equation/inequality and I want to make sure my approach is
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