GMAT Problem Solving (PS) | Re: The shaded portion of the rectangular lot shown above repres

There are two ways to solve it:

1) Factorization

Given y*x= 24*2=48
and x=y+2

(y+2)y=48
y^2+2y-48=0
y=6
Discard y= -8 because side can never be negative

Then
x^2 +y^2= z^2
z=10





2) We know xy= 48

and x-y=2
Square both the sides

(x-y)^2= 2^2
x^2 + y^2 -2xy= 4
x^2 +y^2 =4+ 2*48

x^2 +y^2= 100

Plug this value in the expression: x^2 +y^2= z^2
z=10

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