Formula used: \(\frac{a^x}{a^y} = a^{x-y}\)
\(\frac{4.8(10^9)}{1.6(10^3)}\)
=\(\frac{4.8}{1.6} * \frac{10^9}{10^3}\)
=\(3 * 10^{9-3}\) =\(3 * 10^6\)
Of the answer options,30(10^5) (Option A) has the same value.
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\(\frac{4.8(10^9)}{1.6(10^3)}\)
=\(\frac{4.8}{1.6} * \frac{10^9}{10^3}\)
=\(3 * 10^{9-3}\) =\(3 * 10^6\)
Of the answer options,30(10^5) (Option A) has the same value.
...
