The sum of four consecutive odd numbers is equal to the sum of 3 consecutive even numbers. Given that the middle term of the even numbers is greater than 101 and lesser than 200, how many such sequences can be formed?
check this out,
m = odd number
n = even number
n is 101<n<200, therefore 3 consecutive even numbers will be n-2, n, n+2
and for m it will be m-2, m, m+2, m+4
m-2+m+m+2+m+4=n-2+n+n+2
4m+4=3n
m = 3n/4 - 1
now n is such, 101<n, also, n divisible by 4, and 3n/4 is even so
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check this out,
m = odd number
n = even number
n is 101<n<200, therefore 3 consecutive even numbers will be n-2, n, n+2
and for m it will be m-2, m, m+2, m+4
m-2+m+m+2+m+4=n-2+n+n+2
4m+4=3n
m = 3n/4 - 1
now n is such, 101<n, also, n divisible by 4, and 3n/4 is even so
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