Bunuel wrote:
If 2 is one solution of the equation \(x^2 + b^2x = 12\), where b is a constant, which of the following could be the value of \(bx\)?
I. -12
II. 8
III. 12
A. I only
B. II only
C. III only
D. I and II only
E. I and III only
|
Solution: Answer is E.
4+2b^2=12 => b= +/-(2)
=> x^2 + 4x-12=0
=> (x-2)(x+6)=0
=> x= 2, -6
=> bx= 4,-4,12,-12
Statistics : Posted by rajrishavraj • on 08 Jul 2024, 07:00 • Replies 204 • Views 5172
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