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Problem Solving (PS) | Re: If x^3 < 16x, which of the following CANNOT be true?

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sherifY wrote:

is the reason i cannot cancle out the X here ( so its X^2<16) that they didnt explicitly say x is notzero?

­No, we cannot reduce x^3 < 16x by x. If x > 0, then you'd keep the sign and get x^2 < 16. If x < 0, then you'd flip the sign and get x^2 > 16. 

We cannot multiply or divide an inequality by an unknown or expression containing an unknown without knowing its sign. If the unknown is positive, we should preserve the inequality sign, but if it is negative, we should flip the inequalitysign.

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9.Inequalities



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