ConnectTheDots wrote:
A mixture of sand and cement contains, 3 parts of sand and 5 parts of cement. How much of the mixture must be substituted with sand to make the mixture half sand and half cement?
A. 1/3
B. 1/4
C. 1/5
D. 1/7
E. 1/8
Source: Indian CAT
1.(Initial quantity - quantity removed) *( strength of the mixture) + (Quantity of sand added *strength of sand)/ (initial quantity) =1/2
2. Let initial quantity of the mixture be x and let the quantity removed be y.
3. ((x-y) *5/8) +y*0) / x =1/2, y/x=1/5
Note:
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