KSBGC wrote:
Bunuel wrote:
When the positive integer x is divided by 6, the remainder is 4. Each of the following could also be an integer EXCEPT
(A) \(\frac{x}{2}\)
(B) \(\frac{x}{3}\)
(C) \(\frac{x}{7}\)
(D) \(\frac{x}{11}\)
(E) \(\frac{x}{17}\)
(A) \(\frac{x}{2}\)
(B) \(\frac{x}{3}\)
(C) \(\frac{x}{7}\)
(D) \(\frac{x}{11}\)
(E) \(\frac{x}{17}\)
Note : If any number is not divisible by 3 it's not divisible by 6.
X is not divisible by 6. So, x is not divisible by 3.
The best answer is B.
IMO, this is a very risky assumption. Although it is true that if a number is divisible by 6 it is definitely divisible by 3, the reverse is not true always. 15 is not divisle by 6 but is perfectly divisible by 3.
Correct me if I'm wrong.
Statistics : Posted by Budhaditya_Saha • on 13 Aug 2018, 04:53 • Replies 8 • Views 15533
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