gmatophobia wrote:
Bob expected to spend a total of $9.00 to buy a given amount of pasta salad at a fixed price per pound. However, the price of the salad was $0.20 more per pound than Bob had expected. Consequently, he spent $9.00 and bought\(\frac{1}{2}\) pound less of the salad. How much did Bob spend per pound for the salad?
A. $1.80
B. $1.85
C. $1.90
D. $1.95
E.$2.00
One of the question types in which I would use variables and equations to get to the quadratic and then plug in values. Just using reasoning from options straight away might lead to a lot of time wasted with high possibility of calculation errors.
Whatever you are asked to find, you should prefer to use that as a variable. So price he paid = p and weight he bought = w
pw = 9
Also, as per his initialexpectation,
\( (p -\frac{1}{5} )(w +\frac{1}{2} ) =9\)
\( pw +\frac{p}{2} -\frac{w}{5} -\frac{1}{10} =9\)
\( 2w - 5p =1\) (Eliminate w since we need the value ofp)
\(\frac{18}{p} - 5p =1\)
Now plug in. I know that 18/p will likely be an integer so I will try 2 first. I get -1. Incorrect.
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Statistics : Posted by KarishmaB • on 15 Jul 2023, 06:19 • Replies 14 • Views 16575








