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Problem Solving (PS) | Re: At a post office last week, 25 percent of the employees were part-time

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kayze wrote:

ScottTargetTestPrep wrote:
kayze wrote:
­At a post office last week, 25 percent of the employees were part-time employees and the rest were full-time employees. Each of the part-time employees worked\(\frac{3}{5}\) as many hours as each of the full-time employees last week. The total number of hours worked by the part-time employees last week was what fraction of the total number of hours worked by all of the employees at the post office last week?

A.\(\frac{1}{15}\)
B.\(\frac{1}{9}\)
C.\(\frac{3}{20}\)
D.\(\frac{1}{6}\)
E.\(\frac{1}{5}­\)

Since each part time employee worked 3/5 as many hours as each full time employee, we can let the number of hours worked by each full-time employee be 5 and the number of hours of each part-time employee be3.

Thus, the hours worked by the part-time employees is 1 x 3 = 3 and the total hours worked by all employees is 3 + (3 x 5) =18.

So, the fracton of all hours worked by part-time employees is 3/18 =1/6.

Answer:D


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­Seems like a good candidate for plugging in smart numbers, should have thought of this.Thanks!

­Agree! It's a great place
...

Statistics : Posted by ScottTargetTestPrep • on 21 Jun 2024, 09:35 • Replies 4 • Views 127



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