[textarea] OfficialExplanation
To determine which of the graphs is the correct answer, you first need to determine all values of x that satisfy the inequality. To do that you need to simplify the inequality until you isolate x.
You can begin by multiplying both sides of the inequality by 3 to obtain\( (3)(2-5x)≤ -(6x-5)\) . Note that when you multiply by 3, the right-hand side of the inequality becomes\( -(6x - 5), not -6x -5\) . The rest of the simplification is asfollows.
Note that when an inequality is multiplied (or divided) by a negative number, the direction of the inequality reverses.
The graphs in the answer choices are number lines on which only the number 0 is indicated. Therefore, you do not need to locate 1/9 on the number line; it is enough to know that 1/9 is a positive number. Choice C is the only choice in which the shaded part of the line is equal to or greater than a positive number.
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To determine which of the graphs is the correct answer, you first need to determine all values of x that satisfy the inequality. To do that you need to simplify the inequality until you isolate x.
You can begin by multiplying both sides of the inequality by 3 to obtain\( (3)(2-5x)≤ -(6x-5)\) . Note that when you multiply by 3, the right-hand side of the inequality becomes\( -(6x - 5), not -6x -5\) . The rest of the simplification is asfollows.
\( =(3)(2-5x)≤ - 6x-5\\
\\
=6-15x≤ - 6x-5\\
\\
=-15x≤ -6x-1\\
\\
=-9x≤-1\\
\\
=x≥\frac{1}{9}\)
\\
=6-15x≤ - 6x-5\\
\\
=-15x≤ -6x-1\\
\\
=-9x≤-1\\
\\
=x≥\frac{1}{9}\)
Note that when an inequality is multiplied (or divided) by a negative number, the direction of the inequality reverses.
The graphs in the answer choices are number lines on which only the number 0 is indicated. Therefore, you do not need to locate 1/9 on the number line; it is enough to know that 1/9 is a positive number. Choice C is the only choice in which the shaded part of the line is equal to or greater than a positive number.
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Statistics : Posted by Sajjad1994 • on 19 May 2024, 00:32 • Replies 1 • Views 96










