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Problem Solving (PS) | Re: If x^2 + 10y^2 - 6xy - 2y + 1 = 0, what is the value of x?

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x^2 + 10y^2 - 6xy - 2y + 1 = 0 

10y^2 could be written as 9y^2 + y^2
So:

x^2 + 9y^2 + y^2 - 6xy - 2y + 1 = 0 
x^2 + 9y^2 - 6xy + y^2 - 2y + 1 = 0 
(x-3y)(y-1)=0
y = 1
x = 3y = 3(1)
x=3

Statistics : Posted by Aayushman8 • on 05 Jun 2023, 10:30 • Replies 4 • Views 1638



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