Bunuel wrote:
The circle above has radius 8, and AD is parallel to BC. If the length of arc AYD is twice the length of arc BXC, what is the length of arc BXC?
A. 2π
B. 8π/3
C. 3π
D. 4π
E.16π/3
Attachment:
circle %282%29.jpg
Circumference = 2πr = 2*π*8 = 16π
Arc CD:
Since inscribed angle CAD that intercepts arc CD = 45 degrees, the central angle that intercepts arc CD = 90 degrees, implying that arc CD consititutes 1/4 of the circumference:
1/4 * 16π = 4π
Arc AB:
Since line segments AD and BC are parallel, arcs AB and CD are equal in length.
Thus:
arc AB = 4π
Arc BXC:
Since arcs CD and AB together constitute 8π of the circumference, arcs BXC and AYD must consitute the remaining 8π.
Since BXC:AYD = 1:2 -- a ratio that has 3 parts, 1 of the 3 parts attiributed to arc BXC, the other 2 parts attritubed to arc AYD -- arc BXC must consitute 1/3 of the remaining 8π:
1/3 * 8π =\(\frac{8π}{3}\)
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Statistics : Posted by GMATGuruNY • on 01 May 2018, 06:06 • Replies 9 • Views 7817








